Question
∆ PQR is right-angled at Q. If ∠R = 60º, then find
the value of cosec P.Solution
∠Q = 90°
∠R = 60°
The sum of the angle of the triangle = 180°
90° + 60° + ∠P = 180°
∠P = 30°
Cosec P = Cosec 30° = 2
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