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Let the height of the building be h meters. Let the initial distance from the building be x meters. From the first position: tan 45° = h/x, 1 = h/x, h = x. From the second position (after moving 10 meters closer): tan 60° = h/(x - 10), √3 = h/(x - 10). Now substitute h = x into the second equation: √3 = x/(x - 10). Solving this equation: x/√3 = x - 10 x(√3 - 1)/ √3 = 10 x = 10 (√3 - 1)/ √3 meters. So, the height of the building h = 10 (√3 - 1)/ √3 meters.
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