Question
If sec A + tan A = 3 then the value of cot A
is:Solution
sec A + tan A = 3 ... (1) (sec A + tan A)*(sec A - tan A)/(sec A - tan A) = 11/2 ⇒ (sec2A - tan2A) /(sec A - tan A ) = 11/2 ⇒ 1/(sec A – tan A) = 3 (Since sec2A - tan2A = 1) ⇒ sec A - tan A = 1/3 ... (2) From (1) - (2), we get, 2 tan A = 3 -1/3 = 8/3 ⇒ tan A = 4/3 Therefore, cot A = 1/tan A = 3/4
12, 24, 72, 288, 1440, ?
120     119     ?     352      2464     2455
...12 3 15 ? 153 756
...70    191    47    216    ?    245
105   107   111   114   ?   127
19.11 × 5.98 + 20.03 × 3.12 – 34.95 + 97.9 × 3.02 =?
75    196    52    221    ?    250
5Â Â Â Â Â Â Â Â Â 18Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 44Â Â Â Â Â Â Â Â Â Â Â 83Â Â Â Â Â Â Â Â Â 135Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 200Â Â Â Â ...
3, 4, 10, 33, 136, ?, 4116
If 2.5 3.5 x 30 124 625
Then, x ² - 1 - 2x = ?
...
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