Question
Suppose 140sinĀ²X + 124cosĀ²X = 136 and 184sinĀ²Y +
200cosĀ²Y = 196, then determine the value of 18cosecĀ²XsecĀ²Y.Solution
ATQ,
Since, 140sinĀ²X + 124cosĀ²X = 136
So, 124(sinĀ²X + cosĀ²X) + 16sinĀ²X = 136
Or, 16sinĀ²X = 12
Or, sinĀ²X = 12/16 = 3/4
Or, sinX = ā3/2
So, X = 60ā°
Similarly, Y = 30ā°
So, 18cosecĀ²XsecĀ²Y = 18 Ć 4/3 Ć 4/3 = 32
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