Question
If cos2B = sin(1.5B + 41o), then find the
measure of 'B'.Solution
We know that, cosA = sin(90 o - A) cos2B = sin(1.5B + 41 o) Or, sin(90 o - 2B) = sin(1.5B + 41 o) Or, 90 o - 2B = 1.5B + 41o Or, 2B + 1.5B = 90 o - 41 o So, 3.5B = 49 o So, B = (49 o / 3.5) = 14 o Hence, option b.
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