Question
If sin α + cos β = 2 (0˚ ≤ β < α ≤ 90˚), then
sin[(2α + β)/3] =?Solution
sin α + cos β = 2 sin α ≤ 1; cos β ≤ 1 => α = 90˚ ; β = 0˚ 
sin[(2α + β)/3] = sin (180˚/3) = sin 60˚ = √3/2
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