Question
If Rs. 12000 is invested at a simple interest at the
rate of 5% p.a., Rs. 4800 is obtained as interest in certain years. In order to earn Rs. 6400 as interest on Rs. 20,000 in the same number of years, what should be the rate of simple interest? ÂSolution
S.I = (P Ă—R Ă—T)/100 4800 = (12000 Ă— Â 5 Ă— T)/100 T =4800/600 T = 8 years Similarly, 6400 = (20000 Ă— 8 Ă— R )/100 R = 6400/1600 R = 4% per annumÂ
I. x2 – 39x + 360 = 0
II. y2 – 36y + 315 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
What will be the product of smaller roots of both equations.Â
I. 3x2 - 14x + 15 = 0
II. 15y2 - 34 y + 15 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
Equation 1: 2x2Â - 21x + 54 = 0
Equation 2: 4y2Â - 23y + 15 = 0
Difference between the roots of equation 1 is approx...
I. 4x² -  15x + 9 = 0
II. 20y² -  23y + 6 = 0
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. x² - 8x + 15 = 0 ...
I. 3x2Â + 3x - 60 = 0Â Â Â Â Â
II. 2y2Â - 7y + 5 = 0Â
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