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    Question

    If x runs are second by Rohit, y runs by Shreyas and z

    runs by Virat, then x : y = y : z = 3:2. If total number of runs scored by Rohit, Shreyas and Virat is 304, the find the number of runs scored by Shreyas?  
    A 120 Correct Answer Incorrect Answer
    B 96 Correct Answer Incorrect Answer
    C 168 Correct Answer Incorrect Answer
    D 195 Correct Answer Incorrect Answer
    E 144 Correct Answer Incorrect Answer

    Solution

    ⇒ x : y = 3:2 = 9 : 6 ⇒ y : z = 3 : 2 = 6 : 4 ⇒ x : y : z = 9 : 6 : 4 Since total runs scored by Rohit, Shreyas and Virat = 304 ⇒ 9a + 6a + 4a = 304 ⇒ 19a = 304 ⇒ a = 304/19 = 16 Hence, Runs scored by Shreyas = 6 × 16 = 96

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