Question
If x runs are second by Rohit, y runs by Shreyas and z
runs by Virat, then x : y = y : z = 3:2. If total number of runs scored by Rohit, Shreyas and Virat is 304, the find the number of runs scored by Shreyas? ΒSolution
β x : y = 3:2 = 9 : 6 β y : z = 3 : 2 = 6 : 4 β x : y : z = 9 : 6 : 4 Since total runs scored by Rohit, Shreyas and Virat = 304 β 9a + 6a + 4a = 304 β 19a = 304 β a = 304/19 = 16 Hence, Runs scored by Shreyas = 6 Γ 16 = 96
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