Question
I. 3x² + 17 x - 28 = 0 II. 3 y² -22 y +
24 = 0Solution
I. 3x² + 17 x - 28 = 0 3x² - 4 x + 21 x - 28 = 0 x (3 x – 4) + 7 (3 x – 4) = 0 x = - 7 , 4/3 II. 3 y² -22 y + 24 = 0 3 y² - 18 y - 4 y + 24 = 0 3 y(y – 6) – 4(y – 6) = 0 (3 y – 4) (y – 6) = 0 y = 6, 4/3 Hence, x≤y
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