Question
Quantity-I: Determine the
lateral surface area of a cube where the length of each edge is 'y' cm. Here, 'y' represents the smallest two-digit number. Quantity-II: The breadth of a cuboid is 25% less than its length. If the cuboid's length is 20 cm and its height is 6 cm, calculate its lateral surface area. In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantity-II and choose the correct option.Solution
ATQ, Quantity I: smallest two-digit number, 'y' = 10 Lateral surface area of cube = 4 × (Edge)2 Therefore, required area = 4 × 102 = 4 × 100 = 400 cm2 So, Quantity I = 400 cm2 Quantity II: Breadth of cuboid = 0.75 × 20 = 15 cm Lateral surface area of cuboid = 2 × (Length + Breadth) × Height Therefore, required area = 2 × (20 + 15) × 6 = 2 × 35 × 6 = 420 cm2 So, Quantity II = 420 cm2 Therefore, Quantity-I < Quantity-II
Simplify and express as a fraction:
1.2 ÷ 0.3 + 0.75
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