Question
Person P allocated 65% of the
money he had between X and Y in a ratio of 6:7. Both Y and X invested the amounts they received in a scheme offering 8% simple interest and 7% simple interest for five years, respectively. Given that the difference in the interests earned by X and Y after five years is Rs. 1890, determine the amount remaining with P.Solution
ATQ, Let the amount of money P had initially = Rs. a Amount distributed between X and Y = Rs. 0.65a Amount received by X = 0.65a × 6/13 = Rs. 0.3a Amount received by Y = 0.65a × 7/13 = Rs. 0.35a Interest earned Y = 0.35a × 0.08 × 5 = Rs. 0.14a Interest earned by X = 0.3a × 0.07 × 5 = Rs. 0.105a According to question: 0.14a – 0.105a = 1890 0.035a = 1890 a = 54000 So the amount left with P = 0.35 × 54000 = Rs.18,900
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2Â
The sum of two numbers is 16 and their product is 63. The sum of their reciprocal is equal to:
10% of 100 + 14 = ?% of 120
18, 25, 33, 42, 52, 63, ?
24% of 35% of (5/8) of 2400 = ?Â
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
(1/8) × (256 × 2)/(8 × 4) + ?3 = 1730
What will come in the place of question mark (?) in the given expression?
(20% of 820 – 56 + 11 × 8) 1/2 = ? – 62
375% of 320 - 80% of 40 ÷ √256 = ?
