Question
I. 2x² + 11x + 12 = 0 II. 2y² + 19y +
45 = 0Solution
I. 2x² + 11x + 12 = 0 2x² + 8x + 3x + 12 = 0 2x (x + 4) + 3 (x + 4) = 0 (2x + 3) (x + 4) = 0 x = - 4, -3/2 II. 2y² + 19y + 45 = 0 2y² + 10y + 9y + 45 = 0 2y (y + 5) + 9 (y + 5) = 0 y = - 5, - 9/2 Hence, x > y
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