Question
Solve the quadratic equations and determine the relation
between x and y: Equation 1: 103x² - 470x + 367 = 0 Equation 2: 107y² - 504y + 397 = 0Solution
From Equation 1: 103x² - 470x + 367 = 0 Factorizing: (103x - 367)(x - 1) = 0 So, x = 367/103 or x = 1. From Equation 2: 107y² - 504y + 397 = 0 Factorizing: (107y - 397)(y - 1) = 0 So, y = 397/107 or y = 1. Comparing x and y: x = 367/103, y = 1, x > y x = 1, y = 397/107, x < y x = 1, y = 1, x = y Correct option: E) x = y or no relation
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