Question
I. 14p² + 9p - 8 = 0 II. 4q² - 19q + 12
= 0 In each of these questions two equations numbered I and II are given. You have to solve both the equations and give answer:Solution
I. 14p² + 9p - 8 = 0 14p² +16p -7p - 8 = 0 ⟹ 2p (7p + 8) - 1(7p + 8) = 0 ⟹ (2p - 1)(7p + 8)= 0 ⟹ p = 1/2, -8/7 II. 4q² - 19q + 12 = 0 ⟹ 4 q² - 16q - 3q + 12 =0 ⟹ 4 q(q - 4) - 3(q - 4)= 0 ⟹ (4q - 3) (q - 4)= 0 ⟹ q = 4, 3/4 Hence p < q.
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