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ATQ, l). p ² - 26p +153 =0 p² - 9p – 17p + 153 = 0 (p-9)(p-17) =0 p =9, 17 ll). q²-17q+72=0 q² -9q -8q + 72 = 0 (q-9)(q-8)=0 q =9, 8 Hence, p ≥ q
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