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      Question

      I. 4x2 + 25x + 36 =0 II.

      2y2 + 5y + 3 = 0
      A If x>y Correct Answer Incorrect Answer
      B If x≥y Correct Answer Incorrect Answer
      C If x Correct Answer Incorrect Answer
      D If x≤y Correct Answer Incorrect Answer
      E If x=y or the relationship cannot be established Correct Answer Incorrect Answer

      Solution

      I. 4x2 + 25x + 36 = 0 4x2 + 9x + 16 x + 36 =0 x (4x + 9) + 4 (4x + 9) = 0 (x + 4) (4x + 9) = 0 x = - 4, -9/4 II. 2y2 + 5y + 3 = 0 2y2 + 3y + 2y + 3 = 0 y (2y + 3) + 1 (2y + 3) = 0 (y + 1) (2y + 3) = 0 y = - 1, -3/2 Hence, x<y

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