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    Question

    I. 4x2 + 25x + 36 =0 II.

    2y2 + 5y + 3 = 0
    A If x>y Correct Answer Incorrect Answer
    B If xтЙеy Correct Answer Incorrect Answer
    C If x Correct Answer Incorrect Answer
    D If xтЙдy Correct Answer Incorrect Answer
    E If x=y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 4x2 + 25x + 36 = 0 4x2 + 9x + 16 x + 36 =0 x (4x + 9) + 4 (4x + 9) = 0 (x + 4) (4x + 9) = 0 x = - 4, -9/4 II. 2y2 + 5y + 3 = 0 2y2 + 3y + 2y + 3 = 0 y (2y + 3) + 1 (2y + 3) = 0 (y + 1) (2y + 3) = 0 y = - 1, -3/2 Hence, x<y

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