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    Question

    David alone can complete a work in 15 days and Rizwan

    alone can do the same work in 30 days. David starts the work alone and on every alternate day, Rizwan joins him. In how many days will the work be completed?
    A 12 Correct Answer Incorrect Answer
    B 13 Correct Answer Incorrect Answer
    C 10 Correct Answer Incorrect Answer
    D 14 Correct Answer Incorrect Answer

    Solution

    Given: David finishes work in 15 days тЖТ 1-day work = 1/15 Rizwan finishes in 30 days тЖТ 1-day work = 1/30 Work pattern: Day 1: David Day 2: David + Rizwan Repeats every 2 days 2-day work: Day 1: 1/15 Day 2: 1/15 + 1/30 = 1/10 Total in 2 days = 1/15 + 1/10 = (2 + 3)/30 = 5/30 = 1/6 So, every 2 days тЖТ 1/6 of work is done In 12 days: (12 ├╖ 2) ├Ч 1/6 = 6 ├Ч 1/6 = 1 (full work) Therefore, 12 days is the answer

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