Question
Mixture ‘X’ contains 50% alcohol and the rest 40
litres of water. 150 litres of mixture ‘Y’ contains alcohol and water in the ratio 5:10, respectively. Find the resultant ratio of alcohol to water when these two mixtures are mixed.Solution
ATQ, Quantity of alcohol in mixture ‘X’ = 40 × (0.5/0.5) = 40 litres Quantity of alcohol in mixture ‘Y’ = 150 × (5/15) = 50 litres Quantity of water in mixture ‘Y’ = 150 – 50 = 100 litres Total quantity of alcohol in resultant mixture = 40 + 50 = 90 litres Total quantity of water in resultant mixture = 40 + 100 = 140 litres Required ratio = 90:140 = 9:14
More Mixture Questions
(75 + 0.25 × 10) × 4 = ?2 - 14
Find the value of 'p' in the given expression: 15 of 6 ÷ p x 4 = 30.
6 × 1.8 × 0.25 × 70 = ? + 9.5
23% of 8040+ 42% of 545 = ?%of 3000
?² = 37% of 800 – 14 × 18+ 5! - 20
18 × 15 + 86 – 58 =? + 38
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
- What will come in the place of question mark (?) in the given expression?
389 + 641 - ? = 180 X 2 The value of 15 × 14 – 30 + (32 + 17) is:
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