Question
Mixture ‘X’ contains 50% alcohol and the rest 40
litres of water. 150 litres of mixture ‘Y’ contains alcohol and water in the ratio 5:10, respectively. Find the resultant ratio of alcohol to water when these two mixtures are mixed.Solution
ATQ, Quantity of alcohol in mixture ‘X’ = 40 × (0.5/0.5) = 40 litres Quantity of alcohol in mixture ‘Y’ = 150 × (5/15) = 50 litres Quantity of water in mixture ‘Y’ = 150 – 50 = 100 litres Total quantity of alcohol in resultant mixture = 40 + 50 = 90 litres Total quantity of water in resultant mixture = 40 + 100 = 140 litres Required ratio = 90:140 = 9:14
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