Question
378 ml of mixture ‘A’ contains milk and
water in the ratio 4:5 respectively. If the quantity of milk in mixture ‘B’ is 37.5% more than that in mixture ‘A’ and is 35% of the total quantity of mixture ‘B’ then find the total quantity of mixture ‘B’.Solution
Quantity of milk in mixture ‘A’ = 378 × 4/9 = 168 ml Quantity of water in mixture ‘A’ = 378 - 168 = 210 ml Quantity of milk in mixture ‘B’ = 1.375 × 168 = 231 ml Total quantity of mixture ‘B’ = 231/0.35 = 660 ml
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8