A mixture initially has 40 liters of petrol and an

Solution

ATQ,

Initial Quantity of petrol =40 Liters Initial Quantity of Diesel =60 Liters Quantity of petrol 25% of the mixture = 0.25 × 40 = 10 litres Quantity of diesel in 25% of the mixture = 0.25 × 60 = 15 litres Quantity of petrol after extracted 25% of the mixture= 40 -10 = 30 liters Quantity of diesel after extracted 25% of the mixture= 60 -15 = 45 liters Quantity of petrol after addition of 10 litres of petrol = 30 +10 = 40 liters Ratio of petrol to diesel = 40 : 45 = 8:9 Therefore, I is true. For II: Initial Quantity of petrol =40 Liters Initial Quantity of Diesel =24 Liters Quantity of petrol 25% of the mixture = 0.25 × 40 = 10 litres Quantity of diesel in 25% of the mixture = 0.25 × 24 = 6 litres Quantity of petrol after extracted 25% of the mixture= 40 -10 = 30 liters Quantity of diesel after extracted 25% of the mixture= 24 -6 = 18 liters Quantity of petrol after addition of 10 litres of petrol = 30 +10 = 40 liters Ratio of petrol to diesel = 40 : 18 = 20 : 9 Therefore, II is false. For III: Initial Quantity of petrol = 40 Liters Initial Quantity of Diesel = 48 Liters Quantity of petrol 25% of the mixture = 0.25 × 40 = 10 litres Quantity of diesel in 25% of the mixture = 0.25 × 48 = 12 litres Quantity of petrol after extracted 25% of the mixture= 40 -10 = 30 liters Quantity of diesel after extracted 25% of the mixture= 48 -12 = 36 liters Quantity of petrol after addition of 10 litres of petrol = 30 +10 = 40 liters Ratio of petrol to diesel = 40 : 36 = 10 : 9 Therefore, III is true.