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    Question

    A mixture (paint + thinner) contains paint and thinner

    in the ratio of 9:5, respectively. If 56 litres of the mixture is replaced with 28 litres of thinner, then quantity of paint in the final mixture becomes 32 litres more than that of thinner. Find the initial quantity of the mixture.
    A 182 litres Correct Answer Incorrect Answer
    B 196 litres Correct Answer Incorrect Answer
    C 224 litres Correct Answer Incorrect Answer
    D 266 litres Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the quantity of paint and thinner in the initial mixture be ‘9x’ litres and ‘5x’ litres, respectively Quantity of paint in 56 litres of the mixture
    = 56 × (9/14) = 36 litres Quantity of thinner in 56 litres of the mixture
    = 56 − 36 = 20 litres According to the question, (9x − 36) = (5x − 20 + 28) + 32 Or, 9x − 5x = 36 + 20 + 32 Or, 4x = 76 Or, x = 19 Initial quantity of the mixture
    = 14x = 14 × 19 = 266 litres

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