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ATQ Ratio of milk and water in mixture 'Q' = 6:5 Let the initial quantity of mixture 'Q' be '110x' liters. In mixture 'R': Quantity of milk = (0.30×150×(2/5))+(0.50×110x×(6/11)) = (18+30x) litres Quantity of water = (0.30×150×(3/5))+(0.50×110x×(5/11)) = (27+25x) litres ATQ; 27 + 25x - (18 + 30x) = 10 Or, 30x - 25x = 27 - 10 - 18 So, 'x' = (1/5) = 0.2 Therefore, initial quantity of mixture 'Q' = '110x' = 110 x 0.2 = 22 liters
I. 4x2 + 9x - 9 = 0
II. 4y2 - 19y + 12 = 0
I. x − √2401 = 0
II. y2 − 2401 = 0
I. p² - 10p +21 = 0
II. q² + q -12 = 0
Equation 1: x² - 220x + 12100 = 0
Equation 2: y² - 210y + 11025 = 0
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What will be the product of smaller roots of both equations.
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Equation 1: 33x² - 186x + 240 = 0
Equation 2: 35y² - 200y + ...
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0