Question
Two mixtures, P and Q, have milk-to-sugar ratios of 8:11
and 10:15, respectively. When these two mixtures are combined, the total quantity of the final mixture becomes 0.9 liters, with the milk-to-sugar ratio in the final mixture being 5:7. What was the original quantity of mixture Q before mixing?Solution
ATQ;
Let quantity of milk and sugar in mixture P and Q be 8x ml and 11x ml and 10y ml and 15y ml, respectively.
Quantity of milk in 900 ml of mixture = 5/12 × 900 = 375 ml
Quantity of sugar in 900 ml of mixture = 900 – 375 = 525 ml
So, 8x + 10y = 375
And, 11x + 15y = 525
Solving the above equations, we get;
x = 15 and y = 20
So, quantity of mixture Q = 20 × 25 = 500 ml
612 + 1250 - 728 = ? × 63
What will come in the place of question mark (?) in the given expression?
45% of (√6400 × 5) = ? + 111
(34.88% of 699.79) + 40.030 × 17.88 of 11.86 + 16.21 =? + (7.22)²
(√ 121 x 41) + (3√343 x √289 ) = ? x 19
?2 = (1035 ÷ 23) × (1080 ÷ 24)
(3984 ÷ 24) x (5862 ÷ 40) = ?
√ [? x 11 + (√ 1296)] = 16
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is:
7/11 × 1034 + 1(4/7) × 2401 = 1230 +?
95% of 830 - ? % of 2770 = 650