A 88-litre mixture contains only water and oil in the ratio 6:5, respectively. If 22 litres of the mixture is replaced with the same quantity of oil, then find the quantity of oil in the final mixture.
Amount of oil in the mixture = 88 × (5/11) = 40 litres Amount of oil withdrawn = 22 × (5/11) = 10 litres Quantity of oil in the final mixture = 40 – 10 + 22 = 52 litres
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