Question
A number is picked at random from 1 to 150. What is the
probability that it is either divisible by 6 or by 15 or by both?Solution
ATQ,
Total numbers = 150 Count divisible numbers Divisible by 6 = 150 ÷ 6 = 25 Divisible by 15 = 150 ÷ 15 = 10 Divisible by both (LCM of 6 and 15 = 30): 150 ÷ 30 = 5 Apply inclusion-exclusion Total = 25 + 10 − 5 = 30 Step 3: Probability = 30 / 150 = 1/5 or 0.2
Statements: L < E; M = O; E >K ≥ M
Conclusions:
I. L < M
II. K = O
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Conclusions: I. J < M II. L = J
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Conclusions: I. M = JÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. J < M
...Statements: Q % R & L @ T $ D; W % Q # P
Conclusions :Â Â Â Â Â I. D % RÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. Q % LÂ Â Â Â Â Â Â Â Â Â Â Â Â Â I...
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In the following question the relationship between different elements is given in the statements followed by three conclusions I, II and III. Read the ...
