Question
243! In the trailing Zeros, let us
know.Solution
Products of 2 and 5 always give zero at the end. We need to find a pair of 2 and 5 presents to get the number of zeroes Power of 5 in X! = Â X/5 + X/25 + X/125 + X/625...... (All values are in integer) 243/5 = 48 48/5 = 9 9/5 = 1 Total number of zeros = 48+ 9+ 1 =58 Total number of zeroes is 58.
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