Question
28 men can complete a work in 20 days. 40 women can
complete the same work in 28 days. 20 men and 12 women started working and after 16 days, 20 more women join them. How many days will they now take to complete the remaining work?Solution
Total work done by 28 men and 40 women is equal. Therefore, efficiency of men and women 28 × M × 20 = 40 × W × 28 M : W = 2 : 1 Let Total work = 28 × 2 × 20 = 1120 unit Work done by 20 men and 12 women in 16 days = (20 × 2 + 12 × 1) × 16 = 832 unit Remaining work = 1120 – 832 = 288 unit Total Efficiency (inclusive of 20 women) = 52 + (20 × 1) = 72 Remaining work done in = 288/72 = 4 days
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