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      Question

      If tan 15° = 2 –√3, what is the value of tan 15º

      cot 75°+ tan 75º cot 15°.
      A 8 Correct Answer Incorrect Answer
      B 14 Correct Answer Incorrect Answer
      C 12 Correct Answer Incorrect Answer
      D 10 Correct Answer Incorrect Answer

      Solution

      tan 15° × cot 75° + tan 75° × cot 15° = tan 15° × tan (90° - 15°) + cot (90° -75°) × cot 15° = tan 15° × tan 15° + cot 15° × cot 15° = (tan15°)2 + (cot 15°)2   Now, given tan 15° = 2 - √3 And cot 15° = 1/tan15° = 1/ (2 - √3) = 2 + √3               [on rationalizing]   Thus, tan 15° × cot 75° + tan 75° × cot 15°   = (tan15°)2 + (cot 15°)2 = (2 - √3)2 + (2 + √3)2 = 7 – 4√3 + 7 + 4√3 = 7 + 7 = 14

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