Question
The sum of cost prices of two bikes is ₹1,00,000. One
bike was sold at a profit of 20% and the second one was sold at a loss of 20%. If the selling prices are same, what is the cost price of the first bike sold?Solution
Let the CP of first bike =x and second = (100000-x) Sp of first bike at the 20% profit=x×120/100=120x/100 SP of second bike at the 20% loss =(100000-x) ×80/100 ATQ- 120x/100 =(100000-x) ×80/100 5x =200000 X =40000 Rs.
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