Question
The perimeter of a square field is 10 cm more than the
perimeter of a rectangle. The length of the rectangle is 55 cm which is 250% of its width. If a street of width 10 cm surrounds from outside the square, then find the total cost of constructing the street at the rate of Rs. 20 per sq. cm?Solution
Let the width of the rectangle = x cm Then, 250% of x = 55 x = 55 × 100/250 = 22 cm Perimeter of the rectangle = 2 (length + width) = 2 × (55 + 22) = 154 cm Perimeter of the square = (154 + 10) = 164 cm The sides of the square = 164/4 = 41 cm The area of the square field without street = (41)2 sq. cm = 1681 sq. cm The area of the square field with street = (41 + 20)2 sq. cm = 3721 sq. cm The area of the street = 3721 – 1681 = 2040 sq. cm The total cost of constructing the street = 2040 × 20 = Rs. 40800
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