Question
Two cars cover a certain distance by moving at speeds of
45 km h and 50 km/h respectively. Find the distance traveled when one car takes 32 minutes more than the other to cover the distance.Solution
Let the distance =x km ATQ- x/45 -x/50 =32 (50x -45x)/45×50 =32/60 5x /45×50 =32/60 X = (32×45×50)/60×5 =240km.
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8