Question
Five years ago, the ages of the father and his son were
in the ratio 7:2. Five years hence, the ages of the father and his son will be in the ratio 9:4. After how many years will the father's age be twice the age of his son?Solution
Let the common ratio be x. Hence, five years ago, the ages of the father and his son were 7x and 2x years. According to the question, (7x+5+5) (2x + 5 + 5) = 9:4 28Qx+ 40 = 18x + 90 x = 5 Present age Father = 7x + 5 = 7 x 5 + 5 = 40 Son = 2x + 5 = 2 x 5 + 5 = 15 After P years the father's age will be twice the age of his son. According to the question, 40 + P = 2 x (15 + P) P = 10
What approximate value should replace the question mark?
12.45% of 640.20 − 60% of 2500 = ? − 9000.10
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What value should come in place of question mark (?) in the following question. (You need not to calcualte the exact value)
?/647 = 226/ ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
A, B & C have Rs.1550 together. If they divide the money in the ratio 1:3:1 respectively. Find the difference of amount received by B and C.
What approximate value should come in the place of (?) in the following questions?
∛(92.8 + √1025) * ? = 16.06% of 750
√1024.21 × √624.89 ÷ 4.98 + 11.99 × 4.01 = ?
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
11.11% of (123.45 + 234.56) + 10.01³ - (5.05 of 7.07) = ? of (88.88 - 33.33)
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