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      Question

      A shopkeeper marks up the price of the oil by 40% and

      uses a faulty machine which measures 15% less. If the shopkeeper gives a discount of 32%, the profit/loss percentage is:
      A 15% Loss Correct Answer Incorrect Answer
      B 25% Profit Correct Answer Incorrect Answer
      C 18% Loss Correct Answer Incorrect Answer
      D 12% Profit Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let cost price of 1 liter = 100 Marked price = 100 × 1.4 = 140 Discount 32% → Selling price per “machine liter” = 140 × 0.68 = 95.2 Machine gives 15% less → actual quantity given = 0.85 liter Cost price for 0.85 liter = 100 × 0.85 = 85 Profit = 95.2 − 85 = 10.2 Profit% = (10.2 ÷ 85) × 100 = 12%

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