Question
What is the remainder of function 4a³–12a² +14a–3
when divided by (2a-1)?Solution
Let f(x) =4a³–12a² +14a–3             … (1) Let (2a-1) =0 2a =1 a =1/2 put the value of ‘a’ in EQ (1). 4a³–12a² +14a–3 =4(1/2)3-12(1/2)2+14×1/2-3 =4/8 -3+7-3 = (1/2) +1 =3/2.
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