Question
To do a certain work, the ratio of the efficiencies of
A, B and C is 3:5.8. Working together, they can complete the same work in 15 days. If only A and B work together for 12 days and leave, and then C comes to complete the remaining work, for how many days will C work?Solution
According to the question Time taken by A, B, and C together to complete the same work = [15 x (3 + 5 + 8)] units = (15 x 16) units = 240 units Time taken by A and B together = [(3 + 5) x 12] = (8 x 12) units = 96 units The remaining work = (240-96) units = 144 units Now, Time taken by C to complete the remaining work = (144/8) days = 18 days The required time taken by C to complete the remaining work is 18 days.
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