Question
If θ is an acute angle and sin θ + cosec θ = 2, then
the value of sin⁵ θ + cosec⁵ θ is:Solution
Given – sin + cseccθ = 2, let x = sin θ, then cosec θ =1/x ATQ- x+1/x =2 x²+1 = 2x x²-2x+1 0 (x-1)2 = 0 x-1 =0 x =1. Thus, sin θ = 1, which means θ = 90°. Now, Sin 5 θ = 15=1 Similarly, Cosec5 θ = 1 Therefore, Sin 5 θ + Cosec5 θ =1+1=2 So, the value is 2.
I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
Equation 1: x² - 120x + 3500 = 0
Equation 2: y² - 110y + 3025 = 0
Find the coefficient of x³ in (2x − 3)⁶.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
Find the value of 'x' and 'y' in the following equation:
7x - 2y = 46
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
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