Question
Pipe P and Q can fill a tank in 20 minutes and 30
minutes individually. Another pipe R can empty the tank in 60 minutes. When all the three pipes are opened together then What will be the time taken by them to fill 75% of the capacity of the tank.Solution
ATQ, we can say that The capacity of the tank be = 60 units So, Part of the tank filled by P in 1 minute is = 3 units So, Part of the tank filled by Q in 1 minute = 2 units Therefore, Part of the tank emptied by R in 1 minute = 1 unit So, Part of the tank filled by P, Q and R in 1 minute = 4 units Hence, the Required time will be = [(¾) x 60 x (¼)] = 11.25 minutes
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