📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      Pipe P and Q can fill a tank in 20 minutes and 30

      minutes individually. Another pipe R can empty the tank in 60 minutes. When all the three pipes are opened together then What will be the time taken by them to fill 75% of the capacity of the tank.
      A 12 minutes Correct Answer Incorrect Answer
      B 12.20 minutes Correct Answer Incorrect Answer
      C 10 minutes Correct Answer Incorrect Answer
      D 11.25 minutes Correct Answer Incorrect Answer
      E none of these Correct Answer Incorrect Answer

      Solution

      ATQ, we can say that The capacity of the tank be = 60 units So, Part of the tank filled by P in 1 minute is = 3 units  So, Part of the tank filled by Q in 1 minute = 2 units  Therefore, Part of the tank emptied by R in 1 minute = 1 unit  So, Part of the tank filled by P, Q and R in 1 minute = 4 units Hence, the Required time  will be = [(¾)  x  60  x (¼)] = 11.25 minutes

      Practice Next
      More Pipes and cisterns Questions

      Relevant for Exams:

      ask-question