Question
Tap A can fill a tank in 15 hours. Tap B can fill 12.5%
part of the same tank in 2 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 5/8 part of the tank is filled in 6 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 25% part of the tank?Solution
Tap A alone can fill the tank in = 15 hours. Tap B alone can fill the tank in = (8/1) × 2 = 16 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 6 × (8/5) = 48/5 Taking LCM of 15, 16 and 48/5 =720 Efficiency of Tap A = 48 Efficiency of Tap B = 45 Efficiency of Taps (A + B +C) = 75 Efficiency of Taps (A +C) = 75 – 45 = 30 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (720/30) = 6 hours
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
306, 272, 240, ?, 182, 156
51    52    48     57    ?      66      30
...32, 52, 82, 124, 180, ?
321, 240, ?, 105, 51, 6
6400, 1600, ?, 80, 16, 4
23, 27, 39, 59, ?, 123
7 47 ? 223 359 527
...98, 89, 114, 50, 194, ?
What will come in place of the question mark (?) in the following series?
24, 25, 34, 59, 108, 189, ?
