Question
Tap A can fill a tank in 12 hours. Tap B can fill 20%
part of the same tank in 3 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 5/8 part of the tank is filled in 5 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 35% part of the tank?Solution
Tap A alone can fill the tank in = 12 hours. Tap B alone can fill the tank in = (5/1) × 3 = 15 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 5 × (8/5) = 8 Taking LCM of 12, 15 and 8 =120 Efficiency of Tap A = 10 Efficiency of Tap B = 8 Efficiency of Taps (A + B +C) = 15 Efficiency of Taps (A +C) = 15 – 8 = 7 Tap A and C together take to fill 35% part of the tank in, => (35/100) × (120/7) = 6 hours
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Conclusions:
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II. K = O
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