Question
Tap A can fill a tank in 12 hours. Tap B can fill 20%
part of the same tank in 3 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 5/8 part of the tank is filled in 5 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 35% part of the tank?Solution
Tap A alone can fill the tank in = 12 hours. Tap B alone can fill the tank in = (5/1) × 3 = 15 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 5 × (8/5) = 8 Taking LCM of 12, 15 and 8 =120 Efficiency of Tap A = 10 Efficiency of Tap B = 8 Efficiency of Taps (A + B +C) = 15 Efficiency of Taps (A +C) = 15 – 8 = 7 Tap A and C together take to fill 35% part of the tank in, => (35/100) × (120/7) = 6 hours
13 19 32 52 ? 113
1290, 1225, 1175, ?, 1112, 1095, 1085
? , 864, 432, 144, 36, 7.2
106, 124, 88, 142, ?, 160
What value should come in the place of (?) in the following number series?
5670, 1620, 540, 216, 108, ?
7, 9, 21, ?, 107, 197
71, 79, 88, 152, ?, 393
14, 20, 29, 44, 65, ?
What will come in place of the question mark (?) in the following series?
2.5, 6.5, 18.5, 54.5, 162.5, 486.5, ?
22, 37, 63, 98, 148, ?
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