Question
Pipe ‘A’ can fill a tank in 20 hours while pipe
‘B’ takes 30 hours to empty it. Pipe ‘A’ is opened alone when the tank was empty and after 15 hours pipe ‘B’ is also opened. In how much time will the tank get filled completely?Solution
Let the total capacity of the tank be 60 units Efficiency of pipe ‘A’ = 60/20 = 3 units/hour Efficiency of pipe ‘B’ = 60/30 = 2 units/hour Tank filled in 15 hours = 15 × 3 = 45 units Therefore, required time taken to fill the remaining tank = (60 – 45)/(3 – 2) = 15 hours Therefore, total time taken = 15 + 15 = 30 hours
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
? = 25.08 + 11.99 × 24.07
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
11.67 × 50.23 + ? = 14.88% of 600.44 + 9.66 × 8.272
78% of 1450 + 26² = ? + 1323 ÷ 17
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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