Question
Pipes ‘A’ and ‘B’ can fill a tank in 6 hours and
9 hours, respectively. If pipe ‘C’ is opened along with pipes ‘A’ and ‘B’, then the tank gets filled in 4.5 hours. Find the time taken by pipe ‘C’ to empty (3/5)th part of the same tank.Solution
Let capacity of the tank = 18 litres (lcm of 6 and 9) Efficiency of pipe ‘A’ = (18/6) = 3 litres/hour Efficiency of pipe ‘B’ = (18/9) = 2 litres/hour Efficiency of all the three pipes together = (18/4.5) = 4 litres/hour Efficiency of pipe ‘C’ = 4 – (3 + 2) = (-1) litre/hour {Negative sign shows that pipe ‘C’ is an outlet pipe} Required time taken = {(3/5) × 18)}/1 = 10.8 hours
?% of 320 = 40% of 40 × 5
{(481 + 426) 2 - 4 × 481 × 426} = ?
- What will come in place of the question mark (?) in the following questions?
(? × 3)2 - 85 = 115 × 5 + 69
What will come in the place of question mark (?) in the given expression?
? X √36 - 184 = 62 X 4
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
If A = 0.84181818... then what will be the difference between the numerator and denominator of the lowest fraction form of A?
18% of 200 - 16% of 150 = ?
625 × (?% ÷ 125) = 250% of 10
36 × 15 + 20% 1250 = ? + 296
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