Question
If 8cos 2 A + 3sin 2 A = 9, then
calculate the value of (sec 2 A - 1).Solution
8cos 2 A + 3sin 2 A = 9
Or, 5cos 2 A + 3cos 2 A + 3sin 2 A = 9
Or, 5cos 2 A + 3 X (cos 2 A + sin 2 A) = 9
Or, 5cos 2 A + 3 = 9 (Using, cos 2 A + sin 2 A = 1)
Or, 5cos 2 A = 6
Or, cos 2 A = (6/5)
So, sec 2 A = (5/6) (sec X is reciprocal of cos X)
Required value = (5/6) - 1 = (- 1/6)
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