New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    If 8cos 2  A + 3sin 2  A = 9, then

    calculate the value of (sec 2  A - 1).
    A -1/6 Correct Answer Incorrect Answer
    B -5/6 Correct Answer Incorrect Answer
    C 1/6 Correct Answer Incorrect Answer
    D 5/6 Correct Answer Incorrect Answer

    Solution

    8cos 2  A + 3sin 2  A = 9

    Or, 5cos 2  A + 3cos 2  A + 3sin 2  A = 9

    Or, 5cos 2  A + 3 X (cos 2  A + sin 2  A) = 9

    Or, 5cos 2  A + 3 = 9 (Using, cos 2  A + sin 2  A = 1)

    Or, 5cos 2  A = 6

    Or, cos 2  A = (6/5)

    So, sec 2  A = (5/6) (sec X is reciprocal of cos X)

    Required value = (5/6) - 1 = (- 1/6)

    Practice Next

    Relevant for Exams: