Question
If 8cos 2 A + 3sin 2 A = 9, then
calculate the value of (sec 2 A - 1).Solution
8cos 2 A + 3sin 2 A = 9
Or, 5cos 2 A + 3cos 2 A + 3sin 2 A = 9
Or, 5cos 2 A + 3 X (cos 2 A + sin 2 A) = 9
Or, 5cos 2 A + 3 = 9 (Using, cos 2 A + sin 2 A = 1)
Or, 5cos 2 A = 6
Or, cos 2 A = (6/5)
So, sec 2 A = (5/6) (sec X is reciprocal of cos X)
Required value = (5/6) - 1 = (- 1/6)
What value should come in place of (?) in the given expression.
450 ÷ 9 + 75% of 160 − 64 ÷ 4 = ?
2/5 of 3/4 of 7/9 of 14400 = ?
7/3 of 4/5 of 15/56 of ? = 83
[564 + 32 of 18 × 9 ÷ 12 + 162 ] ÷ 4 = ?
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
45% of 360 - 160 + ? = √324
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
18 × 15 + 86 – 58 =? + 38
√(24²+285-8²-172) = ?²
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