Question
If 8sin²x + 4cos²x − 6 = 0, then find the value of
sinx, given that 0° < x < 90°.Solution
Given
8sin²x + 4cos²x = 6 Or,
8sin²x + 4(1 − sin²x) = 6 Or,
8sin²x + 4 − 4sin²x = 6 Or,
4sin²x = 2 Or,
sin²x = (1/2) Or,
sinx = (1/√2) (since, 0° < x < 90°)
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