Question
If sin5A = cos(2A+20°), then what is the value of A?
Given that 5A is an acute angle.Solution
Always remember that sin & cos are compliment to each other So sin ɵ = cos( 90-ɵ) So it is given that sin5A = cos(2A+20°) Hence 5A + 2A + 20° = 90° So 7A + 20° = 90° or 7A =90°-20° = 70° or A = = 10°
A man is standing at a point 40 meters away from a tower. The angle of elevation of the top of the tower from the point is 45°. After walking 20 meters...
If 2ycosθ = x sinθ and 2xsecθ – ycosecθ = 3, then x 2 + 4y 2 = ?
If tan A = 4/3, 0 ≤ A ≤ 90°, then find the value of sec A.
If x tan 60° + cos 45° = sec 45° then the value of x2 + 1 is
If A, B and C are angles of triangle, then sin2A + sin2B + sin2C– 2cosA cosB cosC
Find the value of tan(75°) using the identity for tan(A+B).
If 2 sec 3x = 4, then the value of x:
If x = r sin A cos B, y = r sin A sin B and z = r cos A, then find x² + y² + z².