Question
Solution
Sec2 θ ( 2 + tan2 θ + cot2 θ) ÷ (sin2θ – tan2θ) \ (cosec2θ + 2 + sec2 θ) (1 + cot2 θ)2 Put θ = 450 = 2(2 + 1 + 1) ÷ (1/2 – 1) / (2 + 2 + 2) (4) = 8 × -2 / 24 = - 2/3
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