Question
Pipe A and Pipe B together can fill the tank in 15
hours. The capacity of the pipe A is 20% of the capacity of the pipe B. How much time will pipe B alone take to fill the tank.Solution
Capacity of the pipe A = 20/100 × Pipe B Pipe A /Pipe B = 1/5 Efficiency of pipe A = 1 units Efficiency of pipe B = 5 units Total work = 15 × (1+5) = 90 units Time taken by Pipe B to fill the tank = 90/5 = 18 hours
Find remainder when 7¹³ is divided by 100.

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