⚡ Month End Offer is live - Get Flat 55% Off on All Courses • Grab it Now! Click Here 00:00:00 AM ⚡

    Question

    Pipe ‘A’ and pipe ‘B’,

    together can fill 20% of a tank in 5 hours while pipe ‘C’ takes 40 hours to empty it. Pipe ‘A’ and pipe ‘B’ were opened together. After 22 hours, pipe ‘C’ is also opened. Find the total time taken to fill the empty tank this way.
    A 60 hours Correct Answer Incorrect Answer
    B 75 hours Correct Answer Incorrect Answer
    C 30 hours Correct Answer Incorrect Answer
    D 45 hours Correct Answer Incorrect Answer
    E 35 hours Correct Answer Incorrect Answer

    Solution

    Time taken by pipe ‘A’ and pipe ‘B’, together to fill the tank = 5/0.20 = 25 hours
    Let the total capacity of tank = 200 units
    Efficiency of pipe (A + B) = 200/25 = 8 units/hour
    Efficiency of pipe ‘C’ = 200/40 = 5 units/hour
    Tank filled by pipe (A + B) in 22 hours = 22 × 8 = 176 units
    Time taken by all three pipes to fill the remaining tank = (200 – 176)/(8 – 5) = 8 hrs
    Total time taken = 22 + 8 = 30 hours

    Practice Next
    More Pipes and cisterns Questions

    Relevant for Exams:

    ask-question