Question
Pipe A can fill the tank in 20 hours. Pipes A and B
together can fill it in 10 hours. Pipes B and C together can fill it in 5 hours. In how many hours can A, B and C together fill the tank?Solution
ATQ, A = 1/20 B = 1/10 − 1/20 B = (2 − 1)/20 = 1/20 B + C = 1/5 C = 1/5 − 1/20 C = (4 − 1)/20 = 3/20 A + B + C = 1/20 + 1/20 + 3/20 = 5/20 Required time = 20/5 hours = 4 hours
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