Question
There are two pipes A & B, pipe A is for filling the
swimming pool and pipe B is to empty the swimming pool. Capacity of swimming pool is 15120 m3 and volume of pipe B is 24 m 3 /minute more than that of pipe A. If pipe A takes 11(1/4) more minutes to fill same swimming pool, than time taken by B to empty the same swimming pool. If pipe B can empty second swimming pool in 102.5 minutes, then find the capacity of second swimming pool?Solution
Let capacity of pipe A = y m3 So, capacity of pipe B = y + 24 m3 Required time to filled the swimming pool = 15120/y minutes Required time to empty the swimming pool = 15120/(y + 24) minutes Accordin to question – 15120/y – 15120 (y + 24) = 45/4 336/y – 336/(y + 24) = 1/4 By solving, y = 168 m3 Capacity of second swimming pool = (168 + 24) × 102.5 = 19680 m3
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?2 = (1035 ÷ 23) × (1080 ÷ 24)
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√(2670+ √(1141+ √(260- √(1251- √(637+ √1521) ) ) ) ) =?
