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    Question

    There are two pipes A & B, pipe A is for filling the

    swimming pool and pipe B is to empty the swimming pool. Capacity of swimming pool is 15120 m3 and volume of pipe B is 24 m 3 /minute more than that of pipe A. If pipe A takes 11(1/4) more minutes to fill same swimming pool, than time taken by B to empty the same swimming pool. If pipe B can empty second swimming pool in 102.5 minutes, then find the capacity of second swimming pool?
    A 22426 m³ Correct Answer Incorrect Answer
    B 24612 m³ Correct Answer Incorrect Answer
    C 19680m³ Correct Answer Incorrect Answer
    D 25810 m³ Correct Answer Incorrect Answer

    Solution

    Let capacity of pipe A = y m3 So, capacity of pipe B = y + 24 m3  Required time to filled the swimming pool = 15120/y minutes   Required time to empty the swimming pool = 15120/(y + 24) minutes Accordin to question – 15120/y – 15120 (y + 24) = 45/4  336/y – 336/(y + 24) = 1/4 By solving, y = 168 m3 Capacity of second swimming pool = (168 + 24) × 102.5 = 19680 m3

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