Question
There are two pipes A & B, pipe A is for filling the
swimming pool and pipe B is to empty the swimming pool. Capacity of swimming pool is 15120 m3 and volume of pipe B is 24 m 3 /minute more than that of pipe A. If pipe A takes 11(1/4) more minutes to fill same swimming pool, than time taken by B to empty the same swimming pool. If pipe B can empty second swimming pool in 102.5 minutes, then find the capacity of second swimming pool?Solution
Let capacity of pipe A = y m3 So, capacity of pipe B = y + 24 m3 Required time to filled the swimming pool = 15120/y minutes Required time to empty the swimming pool = 15120/(y + 24) minutes Accordin to question – 15120/y – 15120 (y + 24) = 45/4 336/y – 336/(y + 24) = 1/4 By solving, y = 168 m3 Capacity of second swimming pool = (168 + 24) × 102.5 = 19680 m3
(500 × 6 ÷ 10) - (√256 + 8) = ?
22% of 400 + √ ? = 34% of 800 - 25% of 400
(2/5)(32% of 4500 – 440) = ? × 8
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
What will come in the place of question mark (?) in the given expression?
96 ÷ (9 - 6.6) + 17.5 X 6 = ? ÷ 8
13 X ? = 85 X 4 + √81 + 2
45% of 360 - 160 + ? = √324
((67)32 × (67)-18 / ? = (67)⁸
4567.89 - 567.89 - 678.89 = ?
82.3 × 644.7 × 723.4 × 815.85 = 72?
