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Let capacity of pipe A = y m3 So, capacity of pipe B = y + 24 m3 Required time to filled the swimming pool = 15120/y minutes Required time to empty the swimming pool = 15120/(y + 24) minutes Accordin to question – 15120/y – 15120 (y + 24) = 45/4 336/y – 336/(y + 24) = 1/4 By solving, y = 168 m3 Capacity of second swimming pool = (168 + 24) × 102.5 = 19680 m3
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