Question
Tap A can fill a tank in 9 hours. Tap B can fill 37.5%
part of the same tank in 3 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 2/5 part of the tank is filled in 2 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 45% part of the tank?Solution
Tap A alone can fill the tank in = 9 hours. Tap B alone can fill the tank in = (8/3) × 3 = 8 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 2 × (5/2) = 5 Taking LCM of 9, 8 and 5 = 360 Efficiency of Tap A = 40 Efficiency of Tap B = 45 Efficiency of Taps (A + B +C) = 72 Efficiency of Taps (A +C) = 72 – 45 = 27 Tap A and C together take to fill 45% part of the tank in, => (45/100) × (360/27) = 6 hours
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